How do you solve for x in (x^2)/(0.100 -x)=1.00e-5?

Question

Pleas help me solve for x in (x^2)/(0.100 -x)=1.00e-5

Answer 1

(x^2)/(0.100 -x) = .00001
x^2 = .000001 - .00001x (multiplying across)
x^2 + .00001x = .000001 (now complete the square)
x^2 + .00001x + .00000000025 = .000001 +.00000000025
(x + .000005)^2 = .00000100025
x = sqrt(.00000100025) +/- .000005

Answer 2

(x^2) / (0.100 - x) = 1.00e-5
x^2 = 1e-5 (1e-1 - x)
x^2 = (1e-1)(1e-5) - (1e-5)x
x^2 - (1e-5)x = (1e-6)
x^2 - (1e-5)x + (5e-6)^2 = (1e-6) + (5e-6)^2
(x - (5e-6))^2 = (1e-6) + (25e-12)
(x - (5e-6))^2 - (1.000025e-6) = 0
x - (5e-6) ± √(1.000025e-6) = 0
x = (5e-6) ± √(1.000025e-6)
x ≈ - 9.950125e-4, 1.0050125e-3
x ≈ - 0.000995, 0.001005