PHYSICS HELP PLEASE Velocity and height?

Question

a wrench falls from a helicoper that is rising steadily at +6.0m/s. After 2.0 seconds

a. what is the velocity of the wrench
and how far below the heliocper is the wrench?

Answer 1

a. Velocity:

(i) After 2 secs the velocity of the wrench RELATIVE to the upwardly moving helicopter is gt DOWNWARDS

= (9.80)t m/s = 19.6m/s downwards.

(ii) However, its DOWNWARDS velocity RELATIVE TO THE GROUND is

(19.6 - 6.0)m/s = 13.6m/s (or - 13.6m/s upwards).

b. Distance:

The wrench is a distance 1/2 g t^2 m = 2*9.80m

= 19.6m below the helicopter.

That is entirely a RELATIVE thing, the constant upwards motion of the helicopter not affecting that relative distance.

Live long and prosper.

Answer 2

v = vo + at

vo is +6 m/s
a is -9.8 m/s^2
t is 2.0 seconds

solve for v

y - yo = vo t + 1/2 a t^2

let yo = 0
vo is +6 m/s
t is 2.0 seconds
a is -9.8 m/s^2

Solve for y