Physics: Quantity of Heat question, Help would be greatly appreciated! :)?

Question

A 15 g bullet traveling horizontally at 865 m/s passes through a tank containing 13.5 kg of water and emerges with a speed of 534 m/s. What is the maximum temperature increase that the water could have as a result of this event?

All that I could think of is using the Quantity of heat equation of course ( Q=mc(change in)T). I have no idea what temperatures to start out with and how to use the velocity. Thanks for any inputs!

Answer 1

loss in KE of bullet = increase in heat content of water + loss in conversion (work into heat)

0.5 mb *(u^2 - v^2) = mw* cp * ∆T + loss
mw* cw * ∆T = 0.5 mb *(u^2 - v^2) - loss
maximum increase in temp (∆T)max will be when LOSS in conversion is considered to be ZERO
mw* cw * (∆T)max = 0.5 mb *(u^2 - v^2)
(∆T)max = 0.5 mb *(u^2 - v^2) /mw*cw
(∆T)max = 0.5*0.015*[865^2 - 534^2] /13.5*4180
(∆T)max = max temp increase =0.062 deg C

Answer 2

floor section: pi r^2 SA = pi * (500^2) SA = 2.5*10^5 pi m^2 SA = 7.80 5 * 10^5 m^2 power = (2 hundred W/m^2) * (7.80 5 * 10^5 m^2) power = a million.fifty seven*10^8 W power = a million.fifty seven*10^8 Joules/sec p of water: one thousand kg/m^3 V = pi * r^2 * h V = pi * (500)^2 * (10) V = 2.5 * 10^6 pi m^3 V = 7.80 5 * 10^6 m^3 Density = mass / volume one thousand = m / ( 7.80 5 * 10^6 ) m = 7.80 5 * 10^9 kg q = mCT a million.fifty seven*10^8 J/s * t sec = (7.80 5*10^9 kg)(4184)(20-10 C) t = 2092000 sec = 24 hours You elevated the speed by ability of the quantity of water as a replace of floor section, so that to procure 10 circumstances a lot less the answer.

Answer 3

you do not need the starting temperature of the water but you want to state your assumptions and it is probably easiest to assume the water is liquid. You also want to assume that all the kinetic energy is converted to heat. Therefore, you know the initial and final kinetic energy of the bullet. You need to find the specific heat of water. You know how much water you have. total energy change = change in kinetic energy of bullet = Cp (Joules/gram/degreeC)*delta T (degreesC)*amt of water (g) good luck