2007-11-17 06:06:17 · 5 answers · asked by michael s 1 in Science & Mathematics ➔ Mathematics
-x^2+7x-10=0
-x^2+5x+2x-10=0 ...(5*2=10 and 5+2=7)
-x(x-5)+2(x-5)=0
(x-5)(2-x)=0....(Taking x-5 common)
either (x-5=0) or (2-x=0)
Case 1:
x-5=0
x=0+5=5
Case 2:
2-x=0
x=2
Therefore x=5 or x=2.
Hope this helps...
2007-11-17 06:24:05 · answer #1 · answered by RJ 1 · 0⤊ 0⤋
-x^2+7x-10=0
Discriminant = 7^2 -4(-10)(-1) = 49 -40 = 9 = 3^2
x1 = (-7 -3)/(-2) = 5
x2 = (-7 +3)/(-2) = 2
2007-11-17 14:09:56 · answer #2 · answered by Any day 6 · 0⤊ 0⤋
x2 = (7 -3)/2 = 2
2007-11-17 14:15:59 · answer #3 · answered by David D 2 · 0⤊ 0⤋
x=[-(7) ± â(7² - 4(-1)(-10))]/2(-1)
=[-7 ± â(9)]/-2
=[-7 ± 3]/-2
x₊ = 3.5 +-1.5 = 2
x₋ = 3.5 - -1.5 = 5
2007-11-17 14:12:47 · answer #4 · answered by DWRead 7 · 0⤊ 0⤋
x = [-7 +/- sqrt(7^2 -4(-1)(-10))]/(28(-1))
x = [-7 +/- sqrt(9)]/-2
x = [-7 +/- 3]/-2
2007-11-17 14:13:18 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋