(x-2)^2=3
2007-11-17 05:55:28 · 8 answers · asked by Katherine G 1 in Science & Mathematics ➔ Mathematics
Take the ±√3 and + 2 like this:
(x - 2)^2 = 3
x - 2 = ±√3
x = ±√3 + 2
2007-11-17 06:04:09 · answer #1 · answered by Igthomque 3 · 0⤊ 0⤋
Take square root,
x-2 = 屉3
x = 2屉3
2007-11-17 13:59:53 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
FOIL:
(x-2)(x-2) = 3
x^2 - 4x + 4 = 3
Now put it in quadratic form by subtracting 3 from each side:
x^2 - 4x + 1 = 0
Now use the quadratic formula to solve:
x = -b +/- (b^2 - 4ac)^1/2 all over 2a
x = (4 +/- (16 - 4*1*1)^1/2 )/ 2
x = (4 +/- (12)^1/2) / 2
x = 2 +/- 3^1/2
Hope this helps!
2007-11-17 14:02:35 · answer #3 · answered by disposable_hero_too 6 · 1⤊ 0⤋
(x-2)^2=3
taking the square root of both sides, we get
x -2 = ± â3
1) x -2 = â3 ---> x = 2 + â3
2) x -2 = - â3 ---> x = 2 - â3
2007-11-17 14:01:17 · answer #4 · answered by Any day 6 · 0⤊ 0⤋
x - 2= +/- â3
x = 2 +/- â3
2007-11-17 14:41:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x-2)²=3
multiyply the square into the "2" and the "X"
X²-2²=3
now do all the squaring u can
X²-4=3
+4+4
add the 4's on both sides to get rid of the "-4" on the left
X² = 7
Square root both sides
âx² = â7
X = 6.45
2007-11-17 14:13:06 · answer #6 · answered by TT.TT 1 · 0⤊ 1⤋
(x-2)^2 = 3
x^2 - 4 = 3
x^2 = 7
x = square root of 7
x = 2.6458
x = - 2.6458
2007-11-17 14:36:32 · answer #7 · answered by Eduardo (lalo) Leal 2 · 0⤊ 0⤋
(x-2)^2=3
Take sqrt both sides getting:
x-2 = +/- sqrt(3)
x = 2 +/- sqrt(3)
2007-11-17 14:01:20 · answer #8 · answered by ironduke8159 7 · 0⤊ 0⤋