3x^2 +8x +4
Discriminant = 8^2 - 4(4)(3) = 64 - 48 = 16 = 4^2
x1 = (-8 -4)/6 = -2
x2 = (-8 +4)/6 = -2/3
2007-11-17 04:59:45
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answer #1
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answered by Anonymous
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3x^2 + 8x + 4 coefficient of 1st and 3rd terms, 3 and 4 product = 12 factors of 12 = 3 × 4 and 6 × 2
out of these 6 + 2 = 8, split the middle term as +6x and + 2x
3x^2 + 6x + 2x + 4 = 0
3x (x + 2) + 2(x + 2) = 0
(3x + 2)(x + 2) = 0
(3x + 2) = 0 or (x + 2) = 0
3x = – 2 or x + 2 = 0
x = – 2/3 or x = – 2
2007-11-17 05:05:55
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answer #2
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answered by Pranil 7
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OK
Try to factoring:
3x^2 + 8x + 4 = 0
(3x+2) (x +2) = 0
x = -2/3 or -2.
Check
3(-2)^2 + 8(-2) + 4 = 0??
12 - 16 + 4 = 0??
0 = 0 YES!!
Hope that helps.
2007-11-17 05:00:54
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answer #3
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answered by pyz01 7
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2 questions right here. enable us to confer with them as Qu a million and Qu 2. Qu a million x² - 8x + sixteen = 0 (x - 4)(x - 4) = 0 x = 4 Qu 2 5 [x² + (3/5)x ] = 4 x² + (3/5)x = 4/5 [ x² + (3/5)x + 9/a hundred ] = 4/5 + 9/a hundred [ (x + (3/10) ] ² = 89/a hundred x + (3/10) = ± ?89 /10 x = (-3/10) ± ?89 /10
2016-12-16 11:27:53
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answer #4
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answered by Anonymous
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First you factor 3x^2+8x+4
The two middle terms will add to 8 (middle number)
and multiply to twelve (first times last number)
Two middle terms are hence 6 and 2
Rewrite then factor
3x^2+6x+2x+4
3x(x+2)+2(x+2)
(3x+2)(x+2)
Now set each parentheses equal to zero to solve
3x+2=0
3x=-2
x=-2/3
x+2=0
x=-2
Your two answers are x=-2/3 and x=-2
You could also solve this using the quadratic formula or completing the square.
2007-11-17 05:02:52
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answer #5
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answered by Shaun B 3
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basically, whenever u have a quadratic equation, such as the one you gave, you can ALWAYS use the same formula to calculate what x actually equals (what the solutions are - in quadratic equations, u always have 2 solutions):
link to the equation is: http://en.wikipedia.org/wiki/Quadratic_equation
look for the part where it says 'quadratic formula'
in the formula, u will find numbers a, b, c which are nothing more then the first, second and third number (preceding the x), so in ur case
a=3
b=8 and
c=4
so when u put these numbers in the equation, you will get the solutions.
this is very useful formula, i would advise u to learn it and use it, because it can be applied to ANY quadratic equation. it is not as complicated as it looks, i personally find this way of solving quadratic equations much easier then the ones shown to u in the answers above.
i hope u find this useful. good luck!
2007-11-17 05:30:47
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answer #6
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answered by Sabi 2
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thats the quadratic formula. if you have a graphing calc. this would be really easy. what you do is press the Y= button on the top left corner of your calc., yhen you plug in xsquared +8x+4 ( the x button is beside the alpha key and says X,T,0,n) then you go over to the graph key on the top right hand coner and press it. the figure should look like a U. then you press the 2nd button then calc ( it says trace on the actual button and is beside graph) then go down to where it says zero ( it should be #2) and press enter then when it says left bound, go as close to the bottom of the x axis as possible and perss enter. then go above the x axis and press enter again. then it'll say guess and don't move the surser just press enter again. then it will say x=-.535894... that is one of your answers. then repete starting with 2nd calc with the other intersection to get your other answer which is
2007-11-17 05:16:15
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answer #7
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answered by Anonymous
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factorize
(3x+2)(x+2)= 0
(3x+2)=0 x = -2/3 or (x+2)=0 x = -2
2007-11-17 05:00:15
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answer #8
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answered by norman 7
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3x^2+8x+4=0
3x^2+2x+6x+4=0
x(3x+2)+2(3x+2)=0
(x+2) (3x+2)=0
(x+2)=0 or (3x+2)=0
x= -2 or x= -2/3
2007-11-17 05:13:37
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answer #9
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answered by pinkcap 2
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3x^2 + 8x + 4 =0
3x^2 + 6x + 2x +4 = 0
3x(x+2) + 2(x + 2) = 0
(3x+2)(x+2) = 0
3x+2=0 or x+2=0
3x=-2 0r x=-2
x= -2/3 or x= -2.
that's it.
2007-11-17 05:09:56
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answer #10
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answered by hogwarts student 2
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