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find a formula for the change in populaetion (P't)
if P(t) is

p(t) = 40(3/2)^t/3

thanx!!!

the answer is:
P'(t) = 40/3 * ln3/2 * (3/2)^t/3

tnanx!!!

2007-11-17 03:44:31 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

iv stated the question and have the answer, dont know how to get it

2007-11-17 03:55:07 · update #1

4 answers

d/dx(a^x) = lna * a^x

Applying the formula your answer comes directly

2007-11-17 03:49:45 · answer #1 · answered by Sheen 4 · 0 0

1. You can put the constant (40) outside of the derivative and just multiply the result by it.

2. The derivative of a^x is a^x * ln a

3. The derivative of a^f(x) is a^f(x) * ln a * the derivative of f(x).
(In your case, f(x) is t/3, and its derivative is 1/3

So, for p(t) = 40(3/2)^t/3

The derivative with respect to t is:

40 [(3/2)^t/3 * ln 3/2 * 1/3]

I hope this helps you see the process.

2007-11-17 11:59:34 · answer #2 · answered by Joe L 5 · 0 0

S(hi)=75/70*integer 8/9^tt
so using this formulae population =shitt

2007-11-17 11:56:04 · answer #3 · answered by helmut UK 3 · 0 0

What is your question?

2007-11-17 11:48:17 · answer #4 · answered by Tony 7 · 0 0

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