Algebra help, please.?

Question

Four times the measure of an angle in 9 more than twice the supplement of the angle. Find the measure of the complement of the angle. (This is very confusing :D)

Answer 1

supplement of an angle = 180degrees minus the angle
complement of an angle = 90degrees minus the angle

let x = the angle
so

Four times the measure of an angle..... 4 x
is 9 more than ........ = 9 +
twice the supplement of the angle ....... 2 ( 180 - x )

4 x = 9 + 2 ( 180 - x )
4 x = 9 + 360 - 2 x
4 x + 2 x = 9 + 360
6 x = 369
x = 369 / 6
x = 61.5

the angle is 61.5 degrees

since you're being asked for the complement angle =

90 - 61.5 = 28.5 degrees

hope this helps!

Answer 2

let suppose the angle is X
the suplement= 180 - x
complement = 90 - x
4x*9=2(180-x)
36x=360-2x
36x+2x=360
38x=360
x=360/38
=> x=9.47
the complement = 90-9.47= 80.53
good luck
m.k.A

Answer 3

lrt the angle be x
according to given conditions we have 4x=9+2(pie-x)
supplement of an angle is pie-x
complement of an angle is pie/2-x
on solving we get x=3/2+pie/3 and required answer is its complement so the ans is pie/2-3/2-pie/3
so ans= pie/6-3/2

Answer 4

the complement of an angle is equal to 90 degrees.
i'm not sure what the equation is because you didn't put it in number form.

Answer 5

Let the angle be x radians. Supplement of x is (π - x). Complement of x is (0.5π - x).

4x - 9 = 2(π - x)
4x - 9 = 2π - 2x
6x = 2π + 9
x = 0.33π + 1.5

Complement of x
= 0.5π - x
= 0.5π - 0.33π - 1.5
= 0.17π - 1.5

Answer 6

For increasing cubic binomials the ordinary formula is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D

Answer 7

isnt this geometry?