2007-11-16 21:52:37 · 7 answers · asked by tony2007 2 in Science & Mathematics ➔ Mathematics
Domain( values of x) is all real numbers
the range( values of y) = 0 -->oo
2007-11-16 22:03:47 · answer #1 · answered by mbdwy 5 · 1⤊ 1⤋
The domain, as many people have said, is the complete set of real numbers. That part is easy.
As for the range, that is indeed [0, infinity), as people have also said. What's inside the absolute value sign has range (-infinity, 2]. So f itself has the range I said.
2007-11-17 13:45:23 · answer #2 · answered by Curt Monash 7 · 0⤊ 0⤋
domain: possible values of x that can satisfy y... (something lyk dat)
therefore i think the domain if that function is the set of all real numbers
2007-11-16 23:00:04 · answer #3 · answered by emoÜ 2 · 0⤊ 1⤋
the domain is the set of x such that x is a member of the real numbers
2007-11-16 22:13:00 · answer #4 · answered by I <3 Taylor Alison Swift 4 · 1⤊ 0⤋
? domain
f(x) = |2-x^2|?
f(x) = 2+x^2
y = 2+x^2
y - 2 = x^2
sqr.rt y -2 = sqr.rt x^2
+/- sqr.rt y -2 = x
The the domain is +/- sqr.rt y -2 = x
2007-11-17 00:03:44 · answer #5 · answered by Anonymous · 0⤊ 1⤋
The domain is all real number, if I'm not mistaken.
2007-11-16 22:00:45 · answer #6 · answered by better_asker 2 · 0⤊ 1⤋
domain is -infinity to infinity
range is x^2>=0
x>=0
and 2-x^2>=2
therefore range isy>=0
2007-11-16 22:09:21 · answer #7 · answered by someone else 7 · 0⤊ 2⤋