Young's modulus problem? Please help!?

Question

A wire that is .002 m in diameter and 1.6 m long stretches .0005 m when a 30 kg weight is hung on its end. Find the Young's modulus of the wire.

Answer 1

E = Tensile stress / tensile strain.

Tensile stress = Force / area
= 30 x 9.8 / [π * 0.001^2] = 9.36 e [7] Pa.

Tensile strain = Increase in length / original length.
= 0.0005 / 1.6 = 3.125 e ( - 4)

E = 2.9952e+11 = 299 .52 G pa.

Answer 2

Y= FL/Al
F- force, L-toltal length of wire, l -extension, A-area of cross section
Answer= 3.15into 10raised to11

Answer 3

Edit:
Used diameter instead of radius, s/b
E = ((30 kg)(9.80665 m/s^2)/(0.00001π m^2))/(0.0005 m/1.6 m)
E = ((30 kg)(1.6 m)(9.80665 m/s^2)/(0.00001π m^2)(0.0005 m)
E ≈ 2.996691*10^10 N/m^2 ≈ 3.00*10^7 KPa