Graph f(x)=4x+1?

Question

Help me please

Answer 1

this sh it is easy, subs x=0 for y-intercept, then subs y=0 for x-intercept, connect the 2 dots, there's your graph!!

Answer 2

This is the same as the equation y=4x+1.

The 1 tells you the line crosses the y-axis at 1 (because the number added or subtracted is called the y-intercept.) Put a dot at one on the y-axis. The slope is 4 which is 4/1 as a fraction. Start at the 1 on the y-axis and move up 4 spaces and right one space. Put a second dot. You have just used the slope ( rise over run) to locate the second point. draw the line.

Answer 3

The +1 tells you your y-intercept (your graph will cross the y-axis at 1) Find your x-intercept by setting the function equal to 0. x-intercept at -1/4. Plot the y and x intercepts to start. The coefficient in front of the x term is your slope. Since it is positive, your line will be increasing from left to right and look like /. The slope equals 4, so for every 4 units you move up, you will move to the right 1 unit. (remember slope equals the change in y over the change in x, and 4 is really 4/1).

Answer 4

Pick several values for x, let's say 0, 1, and 2
Replace the x-values and solve for y.
x = 0, y = 4(0) + 1 = 1
x = 1, y = 4(1) + 1 = 5
x = 2, y = 4(2) + 1 = 9
So, the ordered pairs will be (0, 1), (1, 5), (2, 9).
Connect the dots with a straight line.

Answer 5

This is a line. f(x) is the same as y, so:
y=4x+1
It's a line with slope 4, that runs into the y axis (when x=0) at y=1.

Answer 6

Y=4x+1
This is a straight line which has Gradient 4

You compare it with y=mx+c
Where m is gradient and C is y-intercept.

Answer 7

at x = 0, f(o) = 1
at x = 3, f(3) = 13
Draw a line passing points (0,1) and (3,13)