(x + 6) (x + 5)
Check
(x + 6) (x + 5)
x² + 6x + 5x + 30
x² + 11x + 30 (as required)
2007-11-16 18:49:08
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answer #1
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answered by Como 7
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Whenever the coefficient of x^2 is 1, you have to find the pair of numbers that both multiplies to make the constant (+30) and adds to make the coefficient of x (+11)
5*6 = 30 and 5 + 6 = 11
So, the factored form is (x + 5)(x + 6)
2007-11-16 15:55:37
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answer #2
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answered by Scott K 2
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If it can be factored then the factors are x+a and x+b. Maybe you can see that 30 = a*b, and 11 = a+b. So what are a and b?
In other words, find two numbers whose product is 30 and whose sum is 11. Well, 5 and 6 come to mind. And so the factors must be x+5 and x+6
If this is too hard to understand, maybe you are not ready for this course.
Ben G
2007-11-16 15:58:07
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answer #3
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answered by Ben G 2
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You know that x^2 is x * x
Therefore, you have:
(x * a) (x * b)
To find a and b, ask yourself, "What two numbers add up to get 11 and multiply to get 30?" Why, 5 and 6 do!
Therefore a = 5, b = 6.
Your factorization is (x * 5)(x * 6).
2007-11-16 16:16:48
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answer #4
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answered by Nitro 5
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You see what two numbers multiply to 30 and add up to give you 11.
soo
(x+5)(x+6)=0
solve for x, so you're seeing when the equation equals zero, and know that any number times 0 is 0 so you're trying to make one and then the other equal 0
so -5 and -6 are your answers
2007-11-16 15:55:12
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answer #5
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answered by Anonymous
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this question is in a form of quadratic..so u either can use the formula which is: x= -b ± â (b^2 - 4ac) / 2a where a=1, b=11, and c=30...or u can solve it by factorization: (x+5) (x+6) =0, therefore x=-5, x=-6..
2007-11-16 16:08:32
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answer #6
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answered by toffeedude 2
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(x+6)(x+5)
2007-11-16 16:42:13
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answer #7
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answered by Esquire Angel 2
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(x+5)(x+6)
so x can equal -5,-6
2007-11-16 16:19:19
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answer #8
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answered by makesmegiggle011 3
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(x+5)(x+6)=0
x= -5or-6
2007-11-16 15:52:23
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answer #9
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answered by jiale g 2
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