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2007-11-16 15:49:07 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

(x + 6) (x + 5)
Check
(x + 6) (x + 5)
x² + 6x + 5x + 30
x² + 11x + 30 (as required)

2007-11-16 18:49:08 · answer #1 · answered by Como 7 · 3 1

Whenever the coefficient of x^2 is 1, you have to find the pair of numbers that both multiplies to make the constant (+30) and adds to make the coefficient of x (+11)
5*6 = 30 and 5 + 6 = 11

So, the factored form is (x + 5)(x + 6)

2007-11-16 15:55:37 · answer #2 · answered by Scott K 2 · 0 0

If it can be factored then the factors are x+a and x+b. Maybe you can see that 30 = a*b, and 11 = a+b. So what are a and b?

In other words, find two numbers whose product is 30 and whose sum is 11. Well, 5 and 6 come to mind. And so the factors must be x+5 and x+6

If this is too hard to understand, maybe you are not ready for this course.

Ben G

2007-11-16 15:58:07 · answer #3 · answered by Ben G 2 · 0 1

You know that x^2 is x * x

Therefore, you have:

(x * a) (x * b)

To find a and b, ask yourself, "What two numbers add up to get 11 and multiply to get 30?" Why, 5 and 6 do!

Therefore a = 5, b = 6.

Your factorization is (x * 5)(x * 6).

2007-11-16 16:16:48 · answer #4 · answered by Nitro 5 · 0 1

You see what two numbers multiply to 30 and add up to give you 11.

soo

(x+5)(x+6)=0

solve for x, so you're seeing when the equation equals zero, and know that any number times 0 is 0 so you're trying to make one and then the other equal 0

so -5 and -6 are your answers

2007-11-16 15:55:12 · answer #5 · answered by Anonymous · 0 1

this question is in a form of quadratic..so u either can use the formula which is: x= -b ± √ (b^2 - 4ac) / 2a where a=1, b=11, and c=30...or u can solve it by factorization: (x+5) (x+6) =0, therefore x=-5, x=-6..

2007-11-16 16:08:32 · answer #6 · answered by toffeedude 2 · 0 1

(x+6)(x+5)

2007-11-16 16:42:13 · answer #7 · answered by Esquire Angel 2 · 0 1

(x+5)(x+6)
so x can equal -5,-6

2007-11-16 16:19:19 · answer #8 · answered by makesmegiggle011 3 · 0 1

(x+5)(x+6)=0
x= -5or-6

2007-11-16 15:52:23 · answer #9 · answered by jiale g 2 · 0 0

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