What is the square root of -1?
a. i
b. -1
c. 1
2007-11-16 15:14:16 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Simplify: (5-2i)(3+i)
a. 17 - i
b. 15 + i
c. -17 + i
Simplify: 3/i (Division)
a. -3i
b. -3/i
c. 3i
2007-11-16 15:17:24 · update #1
i^2 ≡ - 1
i ≡ + √- 1
(5-2i) (3+i) =
5 (3+i) - 2i(3+i) =
3*5 + i*5 - 3*2i - i*2i =
15 + 5i - 6i - 2i^2 =
15 - i - 2(- 1) =
15 - i + 2 =
17 - i
(3/i)(i/i) = 3i/i^2 = 3i/(- 1) = - 3i
2007-11-16 15:47:09 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
A negative 1 squared is a positive 1.
2007-11-16 23:22:24 · answer #2 · answered by ginaforu5448 5 · 0⤊ 0⤋
because you can't have a negative # under the square root sign, it's letter a.
there's no such thing as "sqrt of a negative #"
answer is an imaginary #
2007-11-17 06:09:28 · answer #3 · answered by windzard 2 · 0⤊ 0⤋
because you can't have a negative # under the square root sign, it's a.
2007-11-16 23:20:32 · answer #4 · answered by ??? 1 · 0⤊ 0⤋
no answers,-1 cant be square root
2007-11-17 00:09:44 · answer #5 · answered by jiale g 2 · 0⤊ 0⤋
a.
2007-11-16 23:16:46 · answer #6 · answered by fenx 5 · 0⤊ 0⤋