Physics help?

Question

A water bed that is 1.5m wide and 2.5m long weighs 1055 N. Assuming the entire lower surface of the bed is in contact with the floor, what is the pressure the bed exerts on the floor?

Answer 1

First calculate the area of contact: 1.5m X 2.5m = 3.75 sq m.

Then take the load and divide by the area: 1055N/3.75 sq m = 281.33 N/sq m

Answer 2

if the entire lower surface of the bed is equally in contact with the floor, and provided that the floor is flat/level and horizontal, then the pressure exerted by the bed to the floor is uniform, which is:

pressure = 281.33333333333 pascal
pressure = 0.0027765441236929 atmosphere
pressure = 0.0028133333333333 bar
pressure = 2813.3333333333 dyne/centimeter^2
pressure = 0.094214935076489 foot of water
pressure = 0.083077698189232 inch of mercury
pressure = 1.1305792209163 inch of water
pressure = 0.28133333333333 kilonewton/meter^2
pressure = 2.8133333333333 millibar
pressure = 2.1101735340072 millimeter of mercury
pressure = 281.33333333333 newton/meter^2
pressure = 5.8757688309215 pound/foot^2
pressure = 0.040803950214707 pound/inch^2
pressure = 2.1101735340072 torr

Answer 3

Too simple.