If f(x)= 5x+5..., find f'(x)....keep in mind the equation of 5x+5 is square rooted.?

5 ⤊

2007-11-16 14:30:58 · 5 answers · asked by RedSparkle 1 in Science & Mathematics ➔ Mathematics

f'(x)=5/2(5x+5)^-1/2

2007-11-16 14:34:45 · answer #1 · answered by AJ2986 2 · 2⤊ 1⤋

the answer is 5 if f(x) = 5x + 5. What's all this about a square root?

2007-11-16 22:34:07 · answer #2 · answered by Bikki 3 · 0⤊ 1⤋

The derivative is 5.
f(x) = 5x + 5,
therefore f'(x) = 5.

2007-11-16 22:36:16 · answer #3 · answered by C鳡r V 3 · 0⤊ 1⤋

I don't see a square root, but perhaps you meant to write f(x) = â(5x+5)? If so, then:

f'(x)
d(â(5x+5))/dx
1/(2â(5x+5)) d(5x+5)/dx
5/(2â(5x+5))

2007-11-16 22:35:29 · answer #4 · answered by Pascal 7 · 0⤊ 1⤋

Reading as:-
f (x) = (5x + 5)^(1/2)
f ' (x) = (1/2) (5x + 5) ^(-1/2) (5)
f ' (x) = 5 / ( (2) (5x + 5)^(1/2) )

2007-11-17 02:57:00 · answer #5 · answered by Como 7 · 3⤊ 2⤋