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Why doesnt this work? Do not think of the question in any other terms than the way it is presented:

3 brothers pay $10 each for a room for a night.
total $30

Bellhop returns 5 of the $30
each brother keeps a buck and gives the bellhop 2. This reduces each brothers cost by $1 to $9 for a total of $27, bell hop got 2 for a toal of 29 what happened to the 1?

2007-11-16 11:59:55 · 10 answers · asked by roguetrader12002 4 in Science & Mathematics Mathematics

10 answers

You are doing your math incorrectly.

The brothers owed $25 for the room, but they paid $30. They got back $5, but opted to only keep $3. That means they paid $27 total.

The $27 covered:
--> $25 for the room and $2 as a tip to the bell hop.

No dollar is missing.

Another way to look at it:
The original $30 was distributed as follows:
$25 to the hotel, $3 returned to the men, $2 to bell hop.

Again, no contradiction.

2007-11-16 12:05:16 · answer #1 · answered by Puzzling 7 · 1 0

If the bellhop gave back $5, then the cost of the room would have been $25 (30 - 5). This divides unevenly by 3, or $8.3333... Or, using whole numbers, two brothers put in $8 and one put in $9. (8+8+9=25). If the bellhop returned $5, and was allowed to keep $2, the total that each brother paid would have been 9+9+10=28. The $2 tip makes up the difference 28+2=30.

2007-11-16 12:17:57 · answer #2 · answered by ct 2 · 0 0

You are jumping from one money pool to another here:

Each brother did indeed pay $9, so together all 3 paid $27. Of this $27, the hotel got $25 and the bellhop got $2.

Where is the $30?

Originally: brothers = 30, hotel = 0, bellhop = 0 (Total = 30)
After paying: brothers = 0, hotel = 30, bellhop = 0 (Total = 30)
After change: brothers = 5, hotel = 25, bellhop = 0 (Total = 30)
After tip: brothers = 3, hotel = 25, bellhop = 2 (Total = 30)

No money is missing.

Hope this helps! :)

2007-11-16 12:11:13 · answer #3 · answered by disposable_hero_too 6 · 0 0

OK the way i interpret it is if they pay $30 and get back $5 that means that they really pay $25 and if each keeps a buck and they give the bellhop 2 then they really pay $27 .
so therefore $27+$3 would be $30.

or $25+2+3=$30

2007-11-16 12:22:55 · answer #4 · answered by Oreizzle 2 · 0 0

They only paid 27 dollars, not 30, for the hotel. 25 for the room and 2 for the bellhop.

2007-11-16 12:07:27 · answer #5 · answered by Anonymous · 0 0

This statement is wrong:
This reduces each brothers cost by $1 to $9 ...

They were paying (30-5)/3 = $8 1/3,

2007-11-16 12:11:06 · answer #6 · answered by David F 5 · 0 0

The fault is with the questions.
Once the 9 is mutiplied by 3 we get 27.
Now we don't add 2 to this. The 2 is already included in the $27 they paid.
We add 3 which they get back.
Total money before = Cost of product + money you get back.
cost of product is $27 (in which 2 is included) and money you get back is $3.

2007-11-16 12:07:36 · answer #7 · answered by Anonymous · 0 0

it equals $27 the 25 plus tip and the 3 they still have

2007-11-16 12:15:39 · answer #8 · answered by teenmoney 2 · 0 0

one occasion, does not a evidence make. it incredibly is like asserting x^2 = 2x perpetually by way of fact 2*2 = 2+2. address it from the attitude of you're dividing each and each peice greater cases. So whether you have greater peices, by using including the denominators, you're making all of them smaller. i've got not got the time to place it into nifty regularly occurring letters to coach atm, yet i might bypass from: 2/9 and 5/9, the place 2/9 could be

2017-01-05 16:10:39 · answer #9 · answered by ? 3 · 0 0

they either scammed him or its tax

2007-11-16 12:05:26 · answer #10 · answered by Anonymous · 0 2

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