2007-11-16 11:54:51 · 7 answers · asked by de99putt 1 in Science & Mathematics ➔ Astronomy & Space
Pythagoras, a^2 + b^2 = c^2
2007-11-16 11:59:24 · answer #1 · answered by Gary H 7 · 0⤊ 0⤋
10
2007-11-16 20:18:13 · answer #2 · answered by Allie J 2 · 0⤊ 0⤋
Use the distance formula. I don't know how to type up all the symbols, but here's how it goes:
The X from the second set minus the X from the first set. Find the square of that (times it by itself). Then, the Y from the second set minus the Y from the first set. Square that.
Then, add them both together and find the square root of that number. Then, you've got the distance between the two points.
2007-11-16 20:07:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Homecoming queen, you are doing exactly the same operation as Gary, just maybe worded a little differently. You're both using the Pythagorean theorem.
2007-11-16 20:47:44 · answer #4 · answered by Brant 7 · 0⤊ 0⤋
hey gary that is wrong u use thatfor the hypotenuse of a triange the anser is
the square root of 40
distance is the square root of (x2-x1)squared + (y2-y1)squared
if u email me i can show u what the equation looks like
2007-11-16 20:07:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Maybe you'll get better answers in the math or geography sections.
2007-11-16 20:04:27 · answer #6 · answered by morningfoxnorth 6 · 0⤊ 0⤋
x1=-5 y1=3 x2=1 y2=-5
distance=sqrt[(x1-x2)^2+(y1-y2)^2]
=sqrt[(6^2+(-8)^2]
=sqrt(100)=10
2007-11-16 20:08:16 · answer #7 · answered by cidyah 7 · 0⤊ 0⤋