8x^3-6x^2+2x/4x+1
2007-11-16 11:26:00 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x(4x + 1)(x - 1)/(4x + 1)
=2x(x - 1)
Hope this helps, Twiggy.
2007-11-16 11:36:18 · answer #1 · answered by Twiggy 7 · 0⤊ 0⤋
Are you sure the numerator is correct? I'm thinking it should be the following if you want it to come out evenly.
8x^3 - 6x^2 - 2x
Notice the minus before the -2x, rather than +2x.
If you want to solve the problem as written, use synthetic division:
........................ 2x² - 2x
4x + 1 ) 8x^3 - 6x² + 2x
............. 8x^3 + 2x²
.......................... -8x² + 2x
.......................... 8x² - 2x
................................... 4x
So the answer is 2x² - 2x with a remainder of 4x / (4x + 1)
On the other hand, if you meant to write:
8x^3 - 6x^2 - 2x
-----------------------
..... 4x + 1
You can factor out 2x from the numerator:
2x (4x² - 3x - 1)
---------------------
.... 4x + 1
Then factor further as:
2x (4x + 1)(x - 1)
-----------------------
.... (4x + 1)
Cancel the 4x + 1 from top and bottom:
2x (x - 1)
2007-11-16 19:33:19 · answer #2 · answered by Puzzling 7 · 0⤊ 1⤋
the answer is 2x^2 - 2x
it is a little difficult to show my working with long division here
The answer above forgot the 2x factor out, it is not an equation that equals to 0
2x^2 - 2x = 2x(x-1)
okay we are all wrong
the answer is 2x^2 - 2x + 4x/(4x+1)
there is a remainder, but it is -2x not +2x in the quotient
2007-11-16 19:32:46 · answer #3 · answered by norman 7 · 0⤊ 0⤋
factor out 2x in the numerator to get
4x^2-3x-1/4x+1
then factor out the numerator to get
2x(4x+1)(x-1)/4x+1
then the two 4x+1 cancel to get
2x(x-1) as ur answer
2007-11-16 19:32:02 · answer #4 · answered by BOB 2 · 0⤊ 1⤋
Does it equal anything?
2007-11-16 19:31:53 · answer #5 · answered by John M 2 · 0⤊ 1⤋