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2 sin (4 theta) cos (2 theta)
= sin (4 theta) cos (2 theta) + sin (4 theta) cos (2 theta)
= sin (4 theta) cos (2 theta) + cos (4 theta) sin (2 theta)
+sin (4 theta) cos (2 theta) - cos (4 theta) sin (2 theta)
= sin (4 theta + 2 theta) + sin (4 theta - 2 theta)
=sin (6 theta) +sin (2 theta)

2007-11-16 11:25:33 · answer #1 · answered by uk_wildcat96 2 · 0 0

the formula is sina cosb=1/2[sin(a+b) +sin(a-b)]

2sin4acos2a = sin(4a+2a)+sin(4a-2a)]
= sin(6a)+sin(2a)

2007-11-16 19:20:51 · answer #2 · answered by norman 7 · 0 0

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