What is the solution set of the equation x/x-4 -1/x+3= 28/x^2-x-12?

Question

A){4} B){-6} C){ } D){4,-6}

Answer 1

x/(x-4) -1/(x+3) =28/((x-4)(x+3))
x(x+3) - (x-4) = 28
x^2+3x -x+4-28 = 0
x^2 +2x -24 =0
(x+6)(x-4) = 0
x = (4,-6)

Answer 2

ok first 4*87 then divide it by the answer retared