Say I have a glass on a table, in the shape of an inverted frustum of a cone. Upper radius is R[u], lower radius is R[l], height is H. It is filled with soda to a height h.
Question: How far down can I tilt the glass and not spill any soda?
Rephrased: What is the minimum value of theta (0 to 90 degrees) between the table and the side of the glass?
Consider both cases where (1) the bottom of the glass cannot be seen when you've tilted it, and (2) the bottom of the glass can be seen.
2007-11-16 06:18:45 · 4 answers · asked by FredOh F 1 in Science & Mathematics ➔ Mathematics
maybe is interesting to know what are the principles involved because the computations might be complicated
I guess gravitational force has some role too.
2007-11-16 06:28:51 · answer #1 · answered by Theta40 7 · 0⤊ 0⤋
The problem splits into two cases: case 1 in which the water surface in the maximally tilted glass encounters the bottom of the glass, and case 2 in which it does not.
To put it a different way, there will be a critical value of h where the geometry will shift.
Possibly more later.
2007-11-16 06:56:56 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Question: Does the glass have a lid on it?
2007-11-16 06:26:00 · answer #3 · answered by Oak T 2 · 3⤊ 2⤋
who cares?
2007-11-19 08:35:27 · answer #4 · answered by Anonymous · 0⤊ 2⤋