Systems of inequalities!! Help with words problem!!!?

Question

A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 80 hours per week, and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths.

Answer 1

(1) 1x + 2y = 80 The time
(2) x + y = 60 The number of items

Don't know how you're supposed to do this.
Elimination:
Subtract (2) from (1)
x - x + 2y - y = 80 - 60
x-x=0, 2y-y=y, and 80-60=20 so

(3) y = 20
At this point I'd just substitute from (3) back into 2 and get x=40. But we're doing the elimination trip...

So multiply both sides of (2) by 2 and you get
(4) 2x+2y=120
Now subtract (1) from (4) and you get
2x-x + 2y-2y = 120-80.

Since 2x-x = x, 2y-2y=0, and 120-80=40,
(5) x = 40.

Substitution:
Solve (2) for x.
x + y = 60
Add -y to both sides and you get
(6) x = 60-y
Now, substituting from (6) into (1) you get
x + 2y = 80
(60-y) + 2y = 80
Because of the associative property of addition (a+b)+c =a+(b+c), that becomes
60 + (-y + 2y)=80
Doing the arithmetic,
(7) y=20
Substituting from (7) back into (2)
x+y=60
x + 20 = 60
x = 60-20 = 40

I'm not going to take the time to demonstrate that you get the same answers from matrices.

Answer 2

a. Write a gadget of inequalities. x + y = 40 x > y b. what's the optimum form of lily bulbs Jasmine ought to plant? Assuming she has to plant a minimum of one tulip, optimum form of lilies is 39 c. what's the minimum form of lily bulbs? answer: 21

Answer 3

x + 2y =< 80
x+y =< 60
x=> 0
y=>0

Answer 4

x+2y<80

x+y=60, so:
y=60-x

x+2(60-x)<80
x+120-2x<80
40
x>40
so:
y>20

Answer 5

See below. Artie is correct.