what does the square root of 200x / square root of 10 x^-1 =
please show work, thank you
2007-11-16 05:22:02 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sqrt(200x)/sqrt(10x^-1)
we can use the property of roots, nth root(x)/nth root(y) = nth root(x/y)...
sqrt(200x/(10x^-1))
but x^-1 = 1/x, so...
sqrt(200x/(10/x))
simplifying...
sqrt(200x^2/10)
and reducing 200 by 10...
sqrt(20x^2)
sqrt(4*5*x^2)
and the answer is...
2x sqrt(5)
2007-11-16 05:35:33 · answer #1 · answered by mad_vlad 2 · 0⤊ 0⤋
sqrt(200x)/sqrt(10/x)
= sqrt(200x^2/10)
= sqrt (20x^2) = sqrt(4x^2)*sqrt(5) = 2xsqrt(5)
Note that 1o x^-1 = 10/x
2007-11-16 13:29:55 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
(200X)^0.5/(10X^-1)
(200)^0.5X(x)^0.5/(10)^0.5X(x)^-0.5
2XSquareroot5Xx
X= muliplication
2007-11-16 13:51:05 · answer #3 · answered by Murtaza 6 · 0⤊ 0⤋
=sqr(200x)/sqr(10x^-1)
=sqr(200x/10x^-1)
=sqr(20x/x^-1)
=sqr(20x^2)
=x*sqr(20)
=2*x*sqr(5)
2007-11-16 13:26:48 · answer #4 · answered by artie 4 · 0⤊ 0⤋