2007-11-16 04:55:10 · 7 answers · asked by crwlnjeep 4 in Science & Mathematics ➔ Mathematics
6 × x^1/2 = 8 + x
squaring both sides
36 x = 64 +16x + x^2
x^2 – 20 x + 64 =0
x^2 – 16 x – 4x + 64 =0
(x – 4)(x – 16) = 0
(x – 4) = 0 or (x – 16) = 0
x = 4 or x = 16
2007-11-16 05:03:56 · answer #1 · answered by Pranil 7 · 1⤊ 0⤋
6 (square root of x= 8 +x)
6 ( square root of 8)
6 ( square root of 4) ( square root of 2)
6 into2 (square root of2)
12 square root of 2.
2007-11-16 05:14:43 · answer #2 · answered by Sasi Kumar 4 · 0⤊ 0⤋
x=16
2007-11-16 05:04:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
6 x^.5 = 8+x
36x = 64+16x +x^2
x^2-20x +64 = 0
(x-16)(x-4) = 0
x = 4 or x = 16
2007-11-16 05:07:35 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
6 sqrt x =8+x
solution:
squaring both sides.
( 6 sqrt x )^2 = (8+x)^2
6^2 x = ( x + 8)^2
simplify,
36 x = x^2 + 16x + 64
equate to zero,
0 = x^2 + 16x - 36x + 64
0 = x^2 - 20x + 64
using factorization,
0 = ( x -14) (x - 6)
x1 = 14
x2 = 6
hope it helps,
2007-11-16 05:06:11 · answer #5 · answered by Anonymous · 0⤊ 0⤋
this statement would probably be true, if the values of x are approximately 34.125, and 1.875.
thus: x = 34.125
x = 1.875
I obtained this answer using the quadratic formula.
2007-11-16 05:23:06 · answer #6 · answered by Laydee D 1 · 0⤊ 0⤋
no, not at all
2007-11-16 04:59:58 · answer #7 · answered by Dheer T 1 · 0⤊ 0⤋