if the solutions are not exact , estimate the answers by indicating thee consecutive integers between which the roots are located
2007-11-16 04:12:29 · 11 answers · asked by michael s 1 in Science & Mathematics ➔ Mathematics
(x + 8) (x - 1) = 0
x = - 8 , x = 1
2007-11-16 04:31:26 · answer #1 · answered by Como 7 · 2⤊ 1⤋
The above solutions are incorrect because of the fact there are actually not any powers interior the expression. Simplify the equation in the previous fixing for the variable: x(2) - 7x - 8 = 0 2x - 7x - 8 = 0 5x + 8 = 0 5x = -8 x = -8 / 5
2016-10-16 23:31:00 · answer #2 · answered by ? 4 · 0⤊ 0⤋
X^2 + 7x - 8 = 0
solution:
( x + 8) ( x - 1) = 0
x = -8
x = 1
2007-11-16 04:18:46 · answer #3 · answered by Anonymous · 0⤊ 2⤋
x^2 + 7x - 8 = 0
(x + 8)(x - 1) = 0
x + 8 = 0, x = - 8
x - 1= 0, x = 1
Answer: x = - 8, 1
2007-11-16 04:24:37 · answer #4 · answered by Jun Agruda 7 · 2⤊ 1⤋
=(x+8)(x-1) --> x = -8 or 1
2007-11-16 04:18:09 · answer #5 · answered by ironduke8159 7 · 2⤊ 0⤋
x^2 +7x -8=0
x^2 +8x -x -8=0
x(x +8) -1(x+8)=0
(x-1) (x+8)=0 ..... x=1 , x= -8.
2007-11-16 04:51:47 · answer #6 · answered by Sasi Kumar 4 · 0⤊ 1⤋
Use Foil: (x-1)(x+8)
Therefore x= 1, -8
2007-11-16 04:16:59 · answer #7 · answered by Here and There 3 · 0⤊ 1⤋
Answer: x= 1, -8
2007-11-16 04:17:42 · answer #8 · answered by Christian S 2 · 0⤊ 2⤋
x^2+7x-8=(x-8)(x+1)=0
x=8 or x=-1
2007-11-16 04:22:07 · answer #9 · answered by cidyah 7 · 0⤊ 1⤋
x^2+7x-8=0 -8= +8x(-1)
+7= +8-1
x^2+8x-1x-8=0
x(x-8)-1(x-8)=0
(x-8)(x-1)=0
x-8=0 or x-1=0
x=8 or x=1
2007-11-16 04:39:32 · answer #10 · answered by OMASTERSIAYA 1 · 0⤊ 2⤋