2007-11-16 04:08:42 · 11 answers · asked by michael s 1 in Science & Mathematics ➔ Mathematics
Did you notice that it is already factored? Now you have two quantities multiplied together. Now, if the product must equal zero, then one of the two 4p or p-1, must equal zero. The only way the product of two things will equal zero is if one of the things are zero. Therefore, either 4p = 0, or p-1=0, so:
p=0
or
p=1
Then you can substitute these values back into the original equation, and see if you get zero.
2007-11-16 04:15:09 · answer #1 · answered by qspeechc 4 · 0⤊ 1⤋
p = 0 and p = 1
2007-11-16 05:45:04 · answer #2 · answered by Anonymous · 0⤊ 2⤋
p= 0 and p=1
2007-11-16 04:12:35 · answer #3 · answered by gunitsoldier1991 2 · 0⤊ 1⤋
It's already factored. Set each factor =0 getting:
p=0 and p = 1
2007-11-16 04:12:31 · answer #4 · answered by ironduke8159 7 · 2⤊ 0⤋
(4p) (p - 1) = 0 is factored
p = 0 , p = 1
2007-11-16 04:28:30 · answer #5 · answered by Como 7 · 2⤊ 1⤋
Set 4p=0 and solve, so p=0
And set p-1=0 and solve, so p=1
2007-11-16 04:12:38 · answer #6 · answered by pari 3 · 0⤊ 1⤋
Solving:
4p=0 or p-1=0
p=0 or p=1
Now check any conditions which might invalidate either of your two solutions.
2007-11-16 04:13:02 · answer #7 · answered by Sciman 6 · 0⤊ 1⤋
2x² - 3x + a million = 0 the middle term is - 3x discover the sum of the middle term Multiply the 1st term 2 situations the final term a million equals 2 and ingredient the components of two = a million x 2 - 2 and - a million fulfill the sum of the middle term a million = x insert - 2x and - x into the equation 2x² - 3x + a million = 0 2x² - 2x - x + a million = 0 2x(x - a million) - a million(x - a million) = 0 (2x - a million)(x - a million) - - - - - - - - -s-
2016-10-02 12:06:20 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(4p) (p-1) = 0
p=0 and p=1
2007-11-16 04:20:22 · answer #9 · answered by Anonymous · 0⤊ 2⤋
Solve by factoring? It is factored.
2007-11-16 04:11:52 · answer #10 · answered by anthony@three-rs.com 3 · 0⤊ 1⤋