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Light of wavelength 598 nm illuminates a single 0.77 mm wide slit. At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 2.03 mm from the central maximum?

2.614 m, i got this right

What is the width of the central maximum?

no idea i cant seem to get this answer any suggestions...?

2007-11-16 04:06:44 · 2 answers · asked by meeh 1 in Science & Mathematics Physics

2 answers

The full width of the central maximum is just twice the distance to the first minimum. See the ref.

2007-11-17 11:19:22 · answer #1 · answered by kirchwey 7 · 1 4

just double the width of the image on the screen.

.77mm x 2 = 1.54mm for the total width of the central maximum

it has nothing to do with the calculation of part a

2015-04-21 15:36:40 · answer #2 · answered by Christopher 1 · 0 2

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