In theory all particles are having random velocity .
That is to say they have all possible velocities and and in all possible directions. Hence the kinetic energy also differs from particle to particle.
The temperature is the measure of the average kinetic energy of the molecules .
By average, it follows that all particles need not have this energy.
2007-11-15 21:45:30
·
answer #1
·
answered by Pearlsawme 7
·
0⤊
0⤋
No they do not. The energies obey the Boltzmann distribution. The probability of a particle having a certain energy is proportional to exp (-E/kT) where k is the Boltzmann constant. So lower energies are always more likely than higher ones. At very low temperatures, the low energies are extremely preferred. At extremely high temperatures, all energies up to a certain point are pretty much equally likely.
2007-11-15 22:26:08
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
It is not true. For example, in a gas, some molecules are faster, other molecules are slower. The temperature is a measure of the MEAN energy. If you were able to prepare a gas with all its particles moving with the same energy, after a short period they would exchange energy by means of collisions, and the energy distribution would be very close to the Boltzmann law.
2007-11-15 20:19:40
·
answer #3
·
answered by GusBsAs 6
·
0⤊
0⤋
Seems to me you need to look at your working technique. Get yourself properly organised. which includes getting enough sleep, and you won't have these problems. And look up 'Maxwell Boltzmann distribution' [or possibly just 'Boltzmann distribution] in the index of your textbook for the answer to yuor question.
2007-11-15 20:47:55
·
answer #4
·
answered by za 7
·
0⤊
0⤋
No.
They follow the Maxwell-Boltzmann distribution.
2007-11-15 21:53:35
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
well, how is the temperature taken. If it is taken from one specific spot, how would you know all have same KE. If taken over all of surface how would you know if inside was different. I would say no, they do not have all the same KE
2007-11-15 20:18:05
·
answer #6
·
answered by andy g 4
·
0⤊
1⤋
yes
2007-11-15 20:15:58
·
answer #7
·
answered by Errol Vincent B 1
·
0⤊
2⤋