Word Problem Help?

Question

All but 1/16 of the students enrolled at a particular elementary school participated in "Family Fun Night" activities. If a total of 405 students were involved in the evenings activities, how many students attend the school?

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Thanks

Answer 1

x = total # of students attending school
x/16 = # of students who did NOT join the activities
405 = # of students who joined the activities

to get the total # of students, you need to add the # of students who joined the activities and those who did not join the activities.

Therefore...

x = 405 + x/16
x - x/16 = 405
16x/16 - 1x/16 = 405
15x / 16 = 405
15x = 405 * 16
15x = 6480
x = 6480 / 15
x = 432

x = 432 = total # of students

hope this helps!

Answer 2

Let N be the total number of students.

15/16 of the students participated in Family Fun Night, and this was equal to 405 students. So

15 / 16 N = 405

and

N = (405) ( 16 / 15 ) = 432

Answer 3

I am pretty sure you would just multiply 405x16. That will give you 6480 which would be 16/16, or 1. Divide 6480 by 15, because that's how many students came (15/16), and you get 432. That's the total number of students. Hope this helped.

Answer 4

There are 6,480 students at the school.

405 x 16 = 6,480

If it was "all but 1/2", the answer would be 810 students.
same concept...405 x 2

Answer 5

405 x 16 = 6480 students

Answer 6

T - T/16 = 405

16T - T = 6480

15T = 6480

T = 432

Answer 7

Oh, man! I am getting a headache just looking at it!
It definitely brought back bad memories of school days long gone...

Answer 8

let x=total # of students
x/16=participants
x/16=405
x=16*405
x=6480

Answer 9

i have to say...you are something else.

:) good luck