Two identical containers are open at the top and are connected at the bottom via a tube of negligible volume and a valve that is closed. Both containers are filled initially to the same height of 1 m, one with water, the other with mercury. The valve is then opened. Water and mercury are immiscible. Determine the fluid level in the left container (water) when equilibrium is reestablished.
2007-11-15 14:21:23 · 1 answers · asked by Ariel 2 in Science & Mathematics ➔ Physics
Pressure is equal to the product of fluid density p, acceleration due to gravity g and hight above the point of inerest h.
P=pgh
P(left)=P(rigt) when the pressure is balanced
p1gh1 + p2gh2 = p2gh3
p1= 1.0 gm/cm^3
p2= 13.5 gm/cm^3
p1h1 + p2h2 = p2h3
h1=1m
h2+h3=1m
h2= 1- h3
we have
p1h1 + p2h2 = p2(1-h2)
2 p2h2 = p2 -p1h1
h2= (p2 -p1h1)/2p2
h2=(13.5 - 1 x 1)/(2 x 13.5)
h2=0.463 m
left side 1m of water + 0.463m of mercury
left side total = 1.463m
right side 1- 0.463= 0.537 m
2007-11-15 14:29:32 · answer #1 · answered by Edward 7 · 0⤊ 0⤋