A bird flies eastward at a constant angle of 18° to the horizontal?

Question

it flies at this angle and a wind blows directly east at 520 N, it acts with this force due east every 100 meters the bird rises, so how much work is done on the bird during each 100m of its rise by this force... having trouble setting up my free body diagram to determine correct angle and stuff... help please!!!!

Best answer to first correct response, thanks all

Answer 1

The force is due East, so only concern yourself with the horizontal component of motion

100/tan(18) is the horizontal displacement into 520 N

the work is
520*100/tan(18)
=160,000 J

That's a strong bird!

My answer assumes that the bird makes headway against the force so that it is moving ahead related to
tan(18)=100/d
where d is the horizontal distance.

In order to do that, the bird would have to maintain a constant horizontal velocity which requires a force of
520*cos(18) N
or 495 N
and it would have to overcome m*g in the vertical

The work against gravity is m*g*100 for every 100 m of rise.


j