LiOH + CO2 → Li2CO3 + H2O?

Question

LiOH + CO2 → Li2CO3 + H2O



If the percent yield of the above reaction is found to be 92.98 %, how many grams of Li2CO3 are produced from the complete reaction of 119.75 g of LiOH ?

Answer 1

First, divide 119.75 by the molar mass of LiOH to find the used moles of LiOH.

Second, since the ratio of LiOH to Li2CO3 is 1:1 (from the equation), that will be the number of moles of Li2CO3 obtained theoretically.

Third, multiply that by the molar mass of Li2CO3 to find the theoretical yield of Li2CO3 (in grams).

Finally, multiply that by 0.9298 to find the actual yield. Done !!

Answer 2

i will furnish you some rules which will help you resolve this problem and particularly some like it. a million) Convert each and every thing to moles. (they provide you the quantity of LiOH in grams, convert to moles.) 2) Use the molar ratio to be certain how many moles of product you produce. The molar ratio makes each and every thing equivalent (once you have your quantity in moles!). (hence, it fairly is a a million:a million ratio so the moles of reactant = the moles of product.) 3) locate what ninety one.ninety 8% of the moles of H2O you have is. 4) Convert back your answer of moles of H2O back to grams of H2O with the aid of multiplying with the aid of the molecular weight. you ought to use steps, a million, 2, and four in particularly some ordinary questions like this. i desire this permits.