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A child exerts a tangential 41.0 N force on the rim of a disk-shaped merry-go-round with a radius of 2.27 m. If the merry-go-round starts at rest and acquires an angular speed of 0.087 rev/s in 3.54 s, what is its mass?

Help please. I keep getting the wrong answer. Thanks!

2007-11-15 11:17:56 · 1 answers · asked by Tana 1 in Science & Mathematics Physics

1 answers

T = Iα
T = r x F= (1/2)mr^2(ω1 - 0)/(t1 - 0)
m = (2)(41.0 N)(3.54 s) / [(2.27 m)(0.087 rad./s)
m ≈ 1,469.847 kg ≈ 1,470 kg

2007-11-15 11:49:19 · answer #1 · answered by Helmut 7 · 0 0

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