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For the parabola y = 9/Nx^2 + 2x, find the zeros, vertex V(h,k), axis of symmetry and state how you know whether the optimal value (k) is a minimum or maximum

Plz show your steps in answering this question

Thanks a lot for all your help guys.
Really appreciate it.

2007-11-15 10:21:10 · 2 answers · asked by Supreme_edge 2 in Science & Mathematics Mathematics

2 answers

y = (9/N)x^2 + 2x
zeros:
x((9/N)x + 2) = 0
x = 0, (9/N)x = -2
x = 0, x = -2N/9
vertex:
Take the derivative and set it equal to zero:
(18/N)x + 2 = 0
(18/N)x = -2
x = -2N/18 = -N/9
y = (9/N)(-N/9)^2 + 2(-N/9)
y = N/9 - 2N/9 = -N/9
Vertex at (-N/9, -N/9)
If N is positive the parabola "opens up" and k is a minimum
If N is negative the parabola "opens down" and k is a maximum.

2007-11-16 08:06:16 · answer #1 · answered by jsardi56 7 · 0 0

The manufactured from 2 consecutive peculiar integers is 143. locate their sum. So there’s an outstanding extensive form 2n such that (2n-one million)(2n+one million) = 143 4n²-one million = 143 4n²-a hundred and forty four = 0 N²- 36 = 0 (n+6)(n-6) the rationalization I went with 2n±one million became into to be sure the numbers have been peculiar. And it provides me the version of two squares which i understand the thank you to element without needing to think of approximately it. The decrease extensive form 2n-one million=12-one million=11, 04 -12-one million=-thirteen the better extensive form 2n+one million=12+one million=thirteen or -12+one million=-11 So the numbers are -thirteen and -11, or 11 and thirteen the sum is ±24

2017-01-05 14:08:15 · answer #2 · answered by ? 4 · 0 0

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