Dealing with systems of equations, how do you set up 2 equations from the following word problem?

Question

Janice invested $12,000 into two funds. One of the funds returned 6 percent interest and the other returned 8 percent interest after one year. If the toal interest for the year was $880, how much did she invest in each fund?

Answer 1

Let the initial amount in fund 1 (6%) be x and in fund 2 (8%) by y. Then she divided up the money by:

12,000 = x + y

Now a year goes by and she has a total of 12,880 dollars.

12,880 = (1.06)*x + (1.08)* y

The 1.06 is the principal, x plus one year of interest, the 0.06 or 6%. The 1.08 is the principal, y plus 1 year of interest 0.08.

So

12,000 = x + y
12880 = (1.06)x +1.08 y

Hopefully you can solve these from here.

Answer 2

a million) enable w = minutes spent strolling enable 30 - w = minutes spent walking The equation will become: 0.05w + 0.a million(30-w) = 2.5 0.05w + 3 - 0.1w = 2.5 -0.05w = -0.5 w = 10 So, you have walked ten minutes and jogged 20 minutes. 2. The equations with the backside digital camera could be: seven hundred - seven hundred(0.15) = 595 seven hundred - 3 hundred = 4 hundred shop a million has a greater acceptable deal while 15% of the value of the digital camera is larger than $3 hundred. 0.15x > 3 hundred x > 2000 So, if the digital camera at shop one is any quantity over $2000, it particularly is the greater acceptable deal.

Answer 3

X=first fund
Y=second fund

system:
X+Y=12000
X*6/100 + Y*8/100 = 880