the number of molecules in 1.00 liter of O2 gas at 56 degrees Celsius and 821 torr is?

Question

Please explain how you got this answer. Thank you so much!!!

Answer 1

Use ideal gas law!!
You should know: PV = nRT, right?
n is the number of moles of the gas. Timing Avogadro Number and you get the answer:
So: n = PV/RT = (821/760)*1.00/(0.08206*(273+56)) = 0.0400 (mole)
0.0400* 6.022x10^23 = 2.41x10^22 (O2 molecules)