What is the wavelength (m) of a radio frequency is 162.5 MHz ??
2007-11-15 08:48:40 · 4 answers · asked by killakam2422 1 in Science & Mathematics ➔ Physics
Speed equal to the product of wavelength and frequency
c=Lf so wavelength
L=c/f where c=2.99 m/s (speed of light)
L=2.99E+8/162.5 E+6=
L=1.84 m
2007-11-15 09:05:13 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
We all know that distance = velocity X time. Thus L = ct; where L is one wave length, usually measure from crest to crest, c is the velocity of light, and t is the time it takes light to travel one wavelength. We call t the period.
A period is the time it takes a radio wave (light) to go one cycle, where a cycle is L = 2pi radians long by definition. Because t = seconds/cycle, we have 1/t = f = cycles/second and this is what we call frequency. And there we have it.
L = ct = c/f; so that Lf = c. This is important, this tells us that wavelength times frequency must always equal the speed of light c. So if we raise the frequency of a radio transmitter, the wavelength of that radio wave has to decrease to keep the Lf term fixed at c.
OK, then, your question. Lf = c; so that L = c/f = 300,000,000 mps/162.5 X 10^6 cycles/sec. By eyeballing, we see L = c/f = 300 X 10^6/160 X 10^6 ~ 2 meters wavelength. You can do the math.
2007-11-15 09:11:51 · answer #2 · answered by oldprof 7 · 0⤊ 0⤋
Well, 1.844876665 meters (full wave in a vacuum)
2.99792458 x 10 to the 8th meters/second divided by frequency in MHz equals wavelength in meters. (Hz is measured in seconds, therefore, seconds cancel.)
This applies to a free space vacuum. Wave lengths will vary depending on the material (medium) they travel through. 2.99792458 m/sec is the speed of light in a free space vacuum.. 186,282.397 miles/sec could also be used.
To determine frequency divide by wavelength. Remember this formula is for a full wavelength, not 1/4, 1/2, 5/8 or other wavelength.
2007-11-15 09:21:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
d is nice. once you concentrate on the wavelength to be the gap it travels, both holiday at c (velocity of sunshine) then the shorter wavelength photon might want to have a better frequency. for this reason, frequency and wavelength will be proportional. *richard, my apologies for forgetting 'inversely'*
2016-10-24 07:29:28 · answer #4 · answered by desmangles 4 · 0⤊ 0⤋