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The activity of a sample drops by a factor of 10 in 8.0 minutes. What is its half-life?
_______________ min

2007-11-15 08:30:26 · 1 answers · asked by Jessie L 2 in Science & Mathematics Physics

1 answers

OMG it's dead! It's going fast. It has not have a full life... :-(

We can start with a sample on size A and in time t this what is left
A(t)=Aexp(-at)

t= 0 min A(0)=A
t=8 min A(8)=A/10
so substituting time and what we know we have
A/10=Aexp(-a8)
-ln(10)= -a8
a= ln(10) /8

also we can say that fro 1/2 life (half is dead and half is alive!)
(1/2)A=Aexp(-[ln(10)/8] t)
-ln(2)= (-[ln(10)/8] t
t(half life)=ln(2)/[ln(10)/8]
t(1/2)= 2.41 min = 144 s

In general the equation for half life is

t(1/2) = ln(2)/a a - time constant of decay

2007-11-15 08:36:36 · answer #1 · answered by Edward 7 · 2 0

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