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a. (t^2-9)(t^2-9)
b.(t-3)^2(t+3)^2
c.(t-3)(t+3)^2
d.(t-3)(t+3)(t^2+9)

2007-11-15 08:10:27 · 6 answers · asked by BabyGirl82985 1 in Science & Mathematics Mathematics

6 answers

t^4-81 = (t^2 -9)(t^2 +9) = (t-3)(t+3)(t^ +9)

answer is d

2007-11-15 08:15:04 · answer #1 · answered by Anonymous · 0 0

Let u = t^2
t^4 - 81 =
u^2 - 81 =
(u + 9)(u - 9) =
(t^2 + 9)(t^2 - 9) = (t^2 + 9)(t + 3)(t - 3).

2007-11-15 08:16:20 · answer #2 · answered by Darlene 4 · 0 0

use a^2-b^2=(a+b)(a-b) twice

(t^4-81) = (t^2+9)(t^2-9)=(t^2+9)(t+3)(t-3)

so the answer is d

2007-11-15 08:16:00 · answer #3 · answered by norman 7 · 0 0

=t^4-81
=t^2^2-3^2^2
=(t^2+3^2)*(t^2-3^2)
=(t^2+3^2)*(t+3)*(t-3)

2007-11-15 08:34:07 · answer #4 · answered by abhi_comp225 2 · 0 0

the answer is d

2007-11-15 08:14:51 · answer #5 · answered by crackheadezale 1 · 0 0

d and d alone

2007-11-15 08:15:40 · answer #6 · answered by brett s 2 · 0 0

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