6y^2 - 36 = 6y
any help would be greatly appreciated
2007-11-15 07:29:17 · 8 answers · asked by alex 1 in Science & Mathematics ➔ Mathematics
subtract 6x from both sides
6y^2 - 6y - 36 = 0
divide throughout by 6
y^2 - y - 6 = 0
factorise
(y-3)(y+2) = 0
therfore y = 3 or y = -2
2007-11-15 07:33:00 · answer #1 · answered by ajn_death 2 · 0⤊ 0⤋
6y^2-6y =36
6y^2-6y -36= 0
y^2 - y -6 = 0
y = 3 (or) y = -2
2007-11-15 07:34:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋
6y^2-6y-36=0
6(y^2-1y-6)=0
6(y-3)(y+2)=0
y-3=0 or y+2=0
y= 3 or y=-2
2007-11-15 07:34:20 · answer #3 · answered by Anonymous · 0⤊ 0⤋
y^2 -y -6 =0
(y-3)(y+2) = 0
y = 3 or -2
2007-11-15 07:32:44 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
divide by 6 for both sides
y^2-6=y
y^2-y-6=0
(y-3)(y+2)=0
y=3, -2
2007-11-15 07:32:52 · answer #5 · answered by yyc031403 3 · 0⤊ 0⤋
6y^2 - 36 = 6y
-6y -6y
-----------------------
6y - 36 = 0
+ 36 + 36
-----------------------
6y = 36
divide 6 to each side
-----------------------
y = 6
2007-11-15 07:40:13 · answer #6 · answered by Anonymous · 0⤊ 0⤋
1.2
6y^2-36=6y
36y-36=6y
30y=36
y=1.2
2007-11-15 07:35:53 · answer #7 · answered by Mary 3 · 0⤊ 0⤋
y = 3
or
y = -2
i just tried out a bunch of anwsers....
2007-11-15 07:34:41 · answer #8 · answered by Anonymous · 0⤊ 0⤋