2007-11-15 07:03:11 · 6 answers · asked by biomes 1 in Science & Mathematics ➔ Mathematics
what about 1 * -inf? is it still inf
2007-11-15 07:04:57 · update #1
inf*1 = inf
inf*-1 = inf
inf*inf = inf
1/inf = 0
2007-11-15 07:07:18 · answer #1 · answered by Jason 3 · 0⤊ 0⤋
1/inf is 0
2007-11-15 15:06:37 · answer #2 · answered by mathguru 3 · 0⤊ 0⤋
It depends what you mean by infinity.
1/inf is zero though
2007-11-15 15:14:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
inf * 1 = inf
inf -1 = inf
inf * inf = inf
inf * (-1) = MINUS inf
1 * (-inf) = MINUS inf
1/inf approaches zero if you go though a limit process.
2007-11-15 15:07:25 · answer #4 · answered by tkquestion 7 · 0⤊ 0⤋
inf is not a number, so what you wrote is incorrect
The correct notation is
(lim x-->â x )*1 = â
(lim x-->â x )-1 = â
(lim x-->â x )* (lim x-->â x ) = â
1/ (lim x-->â x ) = 0
Just think intuitevely, when x becomes bigger, 1/x becomes smaller and it goes to 0
2007-11-15 15:10:17 · answer #5 · answered by Theta40 7 · 0⤊ 0⤋
1*-inf is -inf
and i think the answer to the first one is yes
2007-11-15 15:06:11 · answer #6 · answered by mimi2424 2 · 0⤊ 0⤋