Help with balancing equations?

Question

Balance this equation:
AgNO3 + Cu -> Cu(NO3)2 +Ag

What type of reaction is this? Why?

How many moles of silver could be produced by reaction of 3.5 moles of copper?

How many grams of silver could be produced by reaction of 3.5 moles copper?

How many atoms of silver could be produced by reaction of 3.5 moles of copper?

How many grams of silver could be produced by reaction of 10.0 grams copper with 50.0 g silver nitrate?

Which reactant is the limiting reactant?

Thanks in advance!
Btw, please explain this as clearly as possible!

Answer 1

2AgNO3 + Cu ===> Cu(NO3)2 + 2Ag

Replacement

3.5molCu x 2molAg/1molCu = 7 moles Ag

7molAg x 6.02x10^23atomAg/1molAg = 4.2 x 10^24 atoms Ag

Atomic weights: Cu=63.5 Ag=108 N=14 O=16 AgNO3=170

10gCu x 1molCu/63.5gCu = 0.157 moles Cu

50.0gAgNO3 x 1molAgNO3/170gAgNO3 = 0.294 moles AgNO3

0.157 moles Cu would require 0.314 moles AgNO3 according to the balanced equation, and you don't have that. So AgNO3 is the limiting reagent.

0.294molAgNO3 x 2molAg/2molAgNO3 x 108gAg/1molAg = 31.8g Ag

Answer 2

2AgNO3+ Cu--->Cu(NO3)2+2Ag
it is a redox reaction because the Ag is reduced and Cu is oxidated (it gains oxigen)
and from Cu3+ goes to Cu2+

7 moles of silver you change the reaction numbers like this 7AgNO3 +3.5 Cu ----> 3.5 Cu(NO3)2+7 Ag

1 mole contains contains 6.022 x 10^23( at the power 23) atoms so 7 x 6.022 x 10^23 atoms

mass of AgNO3=108+(14+16x3)=108 +62 =170
than you find the number of moles in 50.00 grams of AgNO3:
50/170=0.294....=aprox 0.3

than you find the moles in 10 grams of cooper
10/63.5=0.158(aprox)
for the reaction the AgNO3:Cu raport is 2:1 for the total use of the reactans

for our quantity the raport is 0.294 : 0.158 =1.86 : 1 so that means the AgNo3 is in lower quantity for the reaction because 2 is biger than 1.86

that means that all quantity of the AgNO3 will react


further more : 1 mole of AgNO3 contains 108 grams of Ag
and how all the quantity will react (of AgNO3) that means it will result a Quantity of Ag= 0.294 x 108 grams of Ag



AgNO3 look up on the page for the answer

i'll hope you understand if you want more contact me