Area of Triangle = 1/2 * Base * Height
1) A(Triangle) = 1/2 * 8 * 7 = 28cms^2
2) A(Triangle) = 1/2 * 50 * 7 = 175mms^2
Hope that helps
2007-11-15 06:45:11
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answer #1
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answered by gmat g 3
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Area=1/2B*H
4*7=28
25*7=175
2007-11-15 06:46:12
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answer #2
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answered by GodCares 3
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8*7/2 = 28 cm^2
50*7/2 = 175 mm^2
2007-11-15 06:44:59
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answer #3
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answered by ironduke8159 7
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1). A=b*h so 7*8=56 divide 56 by two t. the answer is 28
2) 50*7=350 Divide that by two. Answer is 175
2007-11-15 06:44:37
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answer #4
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answered by SoRealistic 3
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1) 28 cm^2
2) 175 mm^2
2007-11-15 06:48:36
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answer #5
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answered by warcry80 2
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Base times height divided by two
2007-11-15 06:43:32
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answer #6
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answered by JHDillon 2
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a) Use cosine rule to find angle DEF. Let's call that angle "e", then DF^2 = DE^2 + EF^2 - 2(DE)(EF) cos e b) Area = (DE)(EF) sin e /2 OR if you let a = DE, b = EF, c = DF and call s = (a + b + c)/2 (the semi-circumference), than Area = sqrt (s (s-a) (s-b) (s-c) ) Either way should yield the same exact answer.
2016-05-23 07:15:36
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answer #7
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answered by ? 3
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i beleive its 1/2 base X height but i could be wrong...
2007-11-15 06:45:05
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answer #8
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answered by Lizzy 2
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go to mathematical or trig math on the web and get the formula because it looks like you''ll be getting a lot of different answers
2007-11-15 06:48:31
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answer #9
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answered by Anonymous
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56cm
350mm
2007-11-15 06:44:38
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answer #10
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answered by HaNDSAbOY 1
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