what would i^100 be when written in a+bi form when you perform the indicated operation on it?
2007-11-15 06:38:35 · 5 answers · asked by Ayy Girl! 1 in Science & Mathematics ➔ Mathematics
i^100 = (i^2)^50 = (-1)^50 = 1
2007-11-15 06:41:00 · answer #1 · answered by Theta40 7 · 0⤊ 0⤋
Remember i^2 = -1 and i^4 = 1. So,
i^100 = (i^4)^25 = 1
You can write it as 1 + 0i
that's it!
2007-11-15 06:41:35 · answer #2 · answered by Marley K 7 · 0⤊ 0⤋
we know that i^2 = -1
i^100 = (i^2)^50 = (-1)^50 = 1 <== answer
if you want it to be in a+bi form then 1 + 0i is the answer
2007-11-15 06:42:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋
i^100= 1 so a+bi would be a+b
2007-11-15 06:41:31 · answer #4 · answered by Sole 3 · 0⤊ 1⤋
i^100 = (i^4)^25 = 1^25 = 1 = 1 +0i
2007-11-15 06:42:18 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋