Use the point-slope form of the linear equation to find an equation of the line with the given slope and passing through the given point. Then write the equation in standard form.
Slope -4; through (-7, -5)
2007-11-15 05:52:24 · 5 answers · asked by . 1 in Science & Mathematics ➔ Mathematics
OK : point slope form is y = mx +b, where m is the slope and b is the y-intercept.
So : y = -4x + b. Now, you have a point (-7, -5), so lets substitute:
-5 = -4(-7) + b
-5 = 28 + b
-33 = b
So the equation of the line in slope intercept form: y= -4x -33
Now write in standard form:
4x + y = -33
Hope that helps.
2007-11-15 05:58:56 · answer #1 · answered by pyz01 7 · 0⤊ 0⤋
y - -5 = -4(x - -7)
y+5 = -4(x + 7)
y+5 = -4x + -28
y = -4x - 35 (Thats in point-slope form)
2007-11-15 05:55:11 · answer #2 · answered by Laffmaster 2 · 0⤊ 1⤋
4x+y= -33
just in case u wanna know how to solve it. the formula is
y-y1=m(x-x1). m is ur slope. x1 and y1 is the points given. (x=-7,y=-5). You plug it in and then solve it. u should get (y+5)=-4(x+7) then solve it.
2007-11-15 06:01:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
y=mx+b m=4,y= -7, x= -5.....just solve for b and then plug b and m into the equation....y=4x+13
2007-11-15 05:56:15 · answer #4 · answered by boredatwork 4 · 0⤊ 1⤋
y+5=-4(x+7)
or
y=-4x-33
2007-11-15 05:58:27 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋