How much heat is released when a mixture containing 24.7 g of CS2 and 100.0 g Cl2 reacts by the following equa

Question

How much heat is released when a mixture containing 24.7 g of CS2 and 100.0 g Cl2 reacts by the following equation

CS2(g) + 3Cl2(g) S2Cl2(g) + CCl4(g); ΔH = -230. kJ

Answer 1

Atomic weights: C=12 S=32 Cl=35.5 CS2=76 Cl2=71

24.7gCS2 x 1molCS2/76gCS2 = 0.325 mole CS2

100.0gCl2 x 1molCS2/71gCl2 = 1.408 mole Cl2

0.325 mole Cl2 requires only 0.975 mole Cl2, and you have much more than that. So CS2 is the limiting reagent: It will run out first. So then:

0.325molCS2 x -230kJ/1molCS2 = -74.8 kJ

Answer 2

probably just enough............