(5-2i) - (3+i) + (8 + 5i)
How should I go about solving this problem?
2007-11-15 04:47:03 · 4 answers · asked by BrandyJo 3 in Science & Mathematics ➔ Mathematics
add like u add in equations , add the free together & the i together
5-3+8 +(5-1-2)i =10 + 2i
2007-11-15 05:02:15 · answer #1 · answered by mbdwy 5 · 2⤊ 0⤋
Just add numbers seoarayely and ad to sum of imaginary parts:
5-3+8 +(-2-1+5)i = (10 +2i)
2007-11-15 04:55:52 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋
you should separate the problem in to parts:
numbers and i
5-3+8=10
-2i-i+5i=(-2-1+5)i=2i
so answer is
10+2i
2007-11-15 05:07:31 · answer #3 · answered by Ali 2 · 0⤊ 0⤋
First clear the ( ) by distributing the subtraction and addition
5 - 2i - 3 - i + 8 + 5i
Now collect like terms
10 + 2i
2007-11-15 04:51:30 · answer #4 · answered by Linda K 5 · 2⤊ 0⤋