Given the following function, find the indicated values. Then write the corresponding ordered pairs.?

Question

Find h(-1), h(0), and h(3) when h(x) = x^2 - 4x + 4

Answer 1

substitute the value of x into each equation
h(0)=0-0+4=4 (0,4)
h(-1)=1+4+4=9 (-1,9)
h(3)=9-12+4=1 (3,1)

Answer 2

h(-1) = 1+4+4=9 --> (-1,9)
h(0)= 0-0+4 = 4 --> (0,4)
h(3) = 9 -12 + 4 = 1--> (3,1)

Answer 3

h(x)=x^2-4x+4
h(-1)=(-1)^2-4(-1)+4
h(-1)=1+4+4
h(-1)=9
(-1,9)

h(0)=0^2-4(0)+4
h(0)=4
(0,4)

h(3)=3^2-4(3)+4
h(3)=9-12+4
h(3)=1
(3,1)