What volume (L) of 0.332 M potassium hydroxide solution would just neutralize 79.9 ml of 0.345 M H2SO4 solutio

Answer 1

Start with the H2SO4 solution and calculate the number of moles of H2SO4 present:

0.345 mol/L X 0.0799 L = 0.02757 mol H2SO4

Recognize that in the reaction, you will need 2 moles of NaOH to completely neutralize 1 moles H2SO4. So you will need 0.05513 moles of NaOH.

Dividing the moles of NaOH by its concentration will give you the volume (in Liters) of NaOH you need:

0.05513 mol /0.332 mol/L = 0.166 L or 166 mL of NaOH.