what expressioin raised to the 4th power is 81x^12y^8z^16?

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please help me!

2007-11-15 03:12:24 · 2 answers · asked by lele 2 in Science & Mathematics ➔ Mathematics

81 = 3^4
x^12 = [x^3]^4
y^8 = [y^2]^4
z^16 = [z^4]^4

81x^12y^8z^16 = [3x^3y^2z^4]^4

So the answer is 3 x^3 y^2 z^4

2007-11-15 03:16:26 · answer #1 · answered by Astral Walker 7 · 0⤊ 0⤋

since 81 = 3^4,
(3^4)(x^12)(y^8)(z^16) =
[3(x^3)(yÂ²)(z^4)]^4

see how all the exponents were divided by 4?

2007-11-15 11:23:40 · answer #2 · answered by Philo 7 · 0⤊ 0⤋